Give the difference between eclipsed ethane and staggered ethane.

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(N/A) The differences between eclipsed and staggered ethane are as follows:
| Feature | Eclipsed Ethane | Staggered Ethane |
| :--- | :--- | :--- |
| $(i)$ Sawhorse projection | $C-H$ bonds are aligned. | $C-H$ bonds are staggered. |
| $(ii)$ Newman projection | $H$ atoms are directly behind each other. | $H$ atoms are at maximum distance. |
| $(iii)$ Dihedral angle | $0^{\circ}$ | $60^{\circ}$ |
| $(iv)$ Stability | Less stable due to high torsional strain. | More stable due to minimum repulsion. |
| $(v)$ Energy | Higher energy. | Lower energy (by $12.5 \ kJ \ mol^{-1}$). |

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Given below are two statements:
Statement $I$: There are several conformers for $n$-butane. Out of those conformers, the fully eclipsed conformer (dihedral angle $0^{\circ}$) is the least stable and the anti-staggered conformer (dihedral angle $180^{\circ}$) is the most stable.
Statement $II$: As the dihedral angle increases from $0^{\circ}$ to $60^{\circ}$, torsional strain decreases from the fully eclipsed conformer $(X)$ to the gauche conformer $(Y)$.
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In the following Newman projection of the skew conformation of ethane,the dihedral angle between $H'$ and $H''$ is $......^\circ$. (in $^\circ$)

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